[Solved sort of ] (was: org table how to «convert» column formula into row formula)

[Uwe Brauer]

>>> "UB" == Uwe Brauer <oub@mat.ucm.es> writes:

> Hi

> I have the following table 
> | name | pos | rango | weight |
> |------+-----+-------+--------|
> |      |  23 |   329 |    307 |
> |      |  71 |   329 |    259 |
> |      |  77 |   333 |    257 |
> |      |  58 |   333 |    276 |
> |      |  45 |   329 |    285 |
> |      |  47 |   330 |    284 |
> |      |  71 |   329 |    259 |
> |      |  77 |   333 |    257 |
> |      |  77 |   333 |    257 |
> |      | 155 |   310 |    156 |
> |      | 164 |   325 |    162 |
> |      | 203 |   330 |    128 |

> #+TBLFM: $4=($3+1)-$2

> I might be forced to add quite a bit of additional columns to that table
> making it difficult to read. So I thought to transpose the table as
> this, but how can I calculate the last row, using a calc operation.





> | Name   |     |     |     |     |     |     |     |     |     |     |     |  
>    |
> |--------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----|
> | pos    |  23 |  71 |  77 |  58 |  45 |  47 |  71 |  77 |  77 | 155 | 164 | 
> 203 |
> | rango  | 329 | 329 | 333 | 333 | 329 | 330 | 329 | 333 | 333 | 310 | 325 | 
> 330 |
> | weight |     |     |     |     |     |     |     |     |     |     |     |  
>    |

> I tried 


It seems that 
#+Name: row
| Name  |     |     |     |     |     |     |     |     |     |     |     |     
|
|-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----|
| pos   |  23 |  71 |  77 |  58 |  45 |  47 |  71 |  77 |  77 | 155 | 164 | 203 
|
| rango | 329 | 329 | 333 | 333 | 329 | 330 | 329 | 333 | 333 | 310 | 325 | 330 
|
| peso  | 307 | 259 | 257 | 276 | 285 | 284 | 259 | 257 | 257 | 156 | 162 | 128 
|
#+TBLFM: @4$2..@4$13=@3+1-@2

Gives the correct result


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