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From: | John Paul Adrian Glaubitz |
Subject: | Creating bootable CD images for sparc64 |
Date: | Thu, 25 Apr 2019 08:39:08 +0200 |
User-agent: | Mozilla/5.0 (X11; Linux x86_64; rv:60.0) Gecko/20100101 Thunderbird/60.6.1 |
Hi! I'm currently working on switching Debian's installation CDs for sparc and sparc64 to use GRUB instead of SILO for booting from CD. I have modified debian-installer to call grub-mkimage to generate an image of the type sparc64-ieee1275-cdcore which generates a GRUB image for booting. See [1] for a list of modifications that I have made so far (including patches). What I don't know yet is how to actually boot this image. My understanding is that one needs to inject the 512-byte long cdrom.img into a CD using genisoimage or similar tools. But how does the initial boot loader know where to find the GRUB image? Is that actually a fixed string for CD boot? I could not find any reference for that in the GRUB sources. I have briefly also analyzed the DVD image for Oracle Linux for SPARC [2] but that one has both SILO and GRUB files in its boot directory, so I have no idea what it actually uses. Adrian > [1] https://lists.debian.org/debian-sparc/2019/04/msg00036.html > [2] https://mirrors.dotsrc.org/oracle-linux/OL6/U9/x86_64/ -- .''`. John Paul Adrian Glaubitz : :' : Debian Developer - address@hidden `. `' Freie Universitaet Berlin - address@hidden `- GPG: 62FF 8A75 84E0 2956 9546 0006 7426 3B37 F5B5 F913
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