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Re: Define works different when Compile and Eval
From: |
Andrew Tropin |
Subject: |
Re: Define works different when Compile and Eval |
Date: |
Fri, 21 Jun 2024 16:33:42 +0400 |
On 2024-06-19 09:53, Attila Lendvai wrote:
>> (define (test-eval teval)
>> (teval '(define a 1))
>
> if you want this^ to be actually defined while compilation is
> happening (i.e. in the compilation stage; see staged computing), then
> you need to use an (eval-when (expand) ...) wrapper around it.
Thank you for the reply! Not sure what you mean. The following code
defines `a`:
--8<---------------cut here---------------start------------->8---
(define (test-eval teval)
(teval '(define a 1))
(format #t "a value with ~a is ~a\n" teval (teval 'a)))
(test-eval peval)
(test-eval primitive-eval)
(exit 0)
;; a value with #<procedure peval (e)> is 1
;; a value with #<procedure primitive-eval (exp)> is 1
--8<---------------cut here---------------end--------------->8---
The problem and the difference is in how `(define a a)` is evaluated by
compile.
>
> https://www.gnu.org/software/guile/manual/guile.html#Eval-When
>
> compile does not evaluate (aka load) the definitions, it only compiles them.
compile returns value by default, which is probably means that
everything is loaded as well.
> alternatively, you yourself can explicitly call the lambda returned by
> compile.
--8<---------------cut here---------------start------------->8---
(use-modules (system base compile)
(system vm loader))
(define (peval e)
((load-thunk-from-memory
(compile
e
#:to 'bytecode
#:env (resolve-module
'(2024-06-18-define-bug))))))
--8<---------------cut here---------------end--------------->8---
It works the same way as the original code :(
>
> --
> • attila lendvai
> • PGP: 963F 5D5F 45C7 DFCD 0A39
> --
> “A politician is someone asking you to trust them more with power than they
> trust you with freedom...”
> — Kelly Diamond
>
>
>
--
Best regards,
Andrew Tropin
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