printf $variable inside initial parenthesis or use %s?

[Roger]

When using builtin bash printf, which is more appropriate?

printf "$var"

or

printf "%s" $var

(Disregarding proper variable quoting syntax for ensuring proper variable 
expansion.)

My guess, since Bash builtin printf was designed for a drop-in POSIX 
replacement for echo, keep it simple and likely just use the first incantation, 
printf "$var".  While using %s only when fancier printing is required.

I noticed while using the printf %s incantation, I typed double the amount of 
quotes for ensuring proper variable expansion, while also additionally having 
to keep track of the number of %s matched the number of variables to print.  So 
the effort for typing the %s syntax seems more time consuming and is likely 
more prone to typing mistakes.

Roger