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Re: questions about coproc
From: |
Greg Wooledge |
Subject: |
Re: questions about coproc |
Date: |
Thu, 9 Mar 2023 15:04:41 -0500 |
On Thu, Mar 09, 2023 at 03:00:02PM -0500, Grisha Levit wrote:
> On Thu, Mar 9, 2023, 14:34 Grisha Levit <grishalevit@gmail.com> wrote:
>
> > On Thu, Mar 9, 2023, 13:48 Britton Kerin <britton.kerin@gmail.com> wrote:
> >
> >> 1. no obvious way to propagate e.g. the die argument in the above
> >> back to the controlling terminal.
> >
> >
> > Maybe you mean something else by "propagate"
> >
>
> Oh, if you mean capturing the stderr output (without a temp file) you can
> use another coproc for that.
>
> $ coproc e { read -r && echo "$REPLY"; }
> $ coproc c { echo err >&2; } 2>&${e[1]}
> $ read -ru ${e[0]} && echo "$REPLY"
> err
How is that supposed to work when the manual specifically says
There may be only one active coprocess at a time.