Re: How to get a concatenation of the negations with rx (ex: [^a][^b])?

[Emanuel Berg]

Edgar Lux wrote:

> Hello. I am trying to get this regular expression:
>
>     "[^a][^b]"
>
> in an easier way. I thought that I could do
>
>     (rx (not (seq "a" "b")))
>
> but that got me
>
>     Debugger entered--Lisp error: (error "Illegal argument
>     to rx ‘not’: (seq \"a\" \"b\")")
>
> The error is very clear, but I would like to know if there
> is a smart way of achieving the same without having to type:
>
>     (rx (seq (not "a") (not "b")))
>
> which produces
>
>     "[^a][^b]"

(rx (not (any "a" "b")))

"[^ab]"

?

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