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Re: Passing multiple arguments to makefile
From: |
Henrik Carlqvist |
Subject: |
Re: Passing multiple arguments to makefile |
Date: |
Wed, 08 Dec 2010 15:04:08 -0000 |
User-agent: |
Pan/0.14.2 (This is not a psychotic episode. It's a cleansing moment of clarity.) |
Duke Normandin <dukeofperl@ml1.net> wrote:
> I want to do the following:
>
> `make ARGS= "exec_file src_1 src_2 etc"'
>
> I realize that $(ARGS) will contain _all_ the arguments. I need to
> come up with a way to split out each argument to get to:
>
> EXEC-FILE = exec_file
> SRCS = src_1 src_2 src_3
Then why not simply do:
make EXEC-FILE=exec_file SRCS="src_1 src_2 src_3"
But if you really want to use your syntax you could also do:
EXEC-FILE= $(word 1, $(ARGS))
SRCS = $(wordlist 2, 999, $(ARGS))
> I'm trying to create a "generic" makefile for a non-C compiler. Is
> this possible? TIA...
Of course it is possible to do other things than compiling C code. Make
simply tries to create files when it finds that some other files are newer.
This creation of files could be done by running a C compiler, but it could
also be done with any other tool of your choice.
regards Henrik
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