Re: Template member function specialization

[Thomas Maeder]

"martines" <martiness1@REMOVEpoczta.onet.pl> writes:

> struct Simple {
>     template <class T>
>         void fun() {}
>     template <>               // *)
>         void fun<int>() {}    // **)
> };
>
> Can anybody explain what is wrong with the first code and what is the 

The explicit specialization has to be defined in the enclosing
namespace:

struct Simple {
    template <class T>
    void fun() {}
};

template <>
void Simple::fun<int>() {}