Array Problem

[Keith]

Ok, what I am looking for this program to do is compute salary and then use 
a single subscripted array to output the amount of employees that are in 
each pay bracket. ie. 200-299, 300-399 and so forth to 1000. How can I 
accomplish this? I seem to be running into a wall here. Can anyone help? 
Thanks.

//This program computes the amount of employees who receive a salary in a 
set number of ranges.

//Assignment 4.10

#include <iostream>

#include <iomanip>

#include <conio.h>

using std::cout;

using std::cin;

double pay[];

double calculateSalary (double totalEarned){

// regular earning of each employee

double basesalary(200);

// total amount employee brings to company

double earnings(totalEarned);

// percentage of amount employee receives as commision

double commision(earnings * .09);

// total amount employee earns with commision

double totalearned=(commision + basesalary);

return totalearned;

}

int main() //begins program execution

{

double earnings(0);

double totalEarned=0;

while (earnings =! -1)

cout << "Enter total sales for employee (Enter -1 to stop and tabulate) :";

cin >> earnings;

cout << "\nHere is the total salary of employee: $" << 
calculateSalary(earnings);







double pay[] = {200,300,400,500,600,700,800,900,1000};

{

for (i = 0, i < size, i++)

if calculateSalary(earnings) < 300

return 0;

if calculateSalary(earnings) < 400

return 1;

if calculateSalary(earnings) < 500

return 2;

if calculateSalary(earnings) < 600

return 3;

if calculateSalary(earnings) < 700

return 4;

if calculateSalary(earnings) < 800

return 5;

if calculateSalary(earnings) < 900

return 6;

if calculateSalary(earnings) < 1000

return 7;

getch();

return 0;

}