Re: warning with function templates

[BobR]

Christian Christmann wrote in message
<42d902c0$0$18015$9b4e6d93@newsread4.arcor-online.net>...
>Hi,
>
>when I run this code:
>
>#include <iostream>
>using namespace std;
>
>template <class T>
>T GetValue(int a)
>{
>    if (a = 1)
>        return 1;
>    else
>        return 2.55; // line 11
>}
>
>int main()
>{
>    int a = GetValue<int>(1); // line 16
>    cout << "\nInt a : " << a << endl;
>
>    double b = GetValue<double>(2);
>    cout << "\nDouble b: " << b << endl;
>
>    return 0;
>}
>
>I get the gcc warning:
>temp.cpp: In function `T GetValue(int) [with T = int]':
>temp.cpp:16:   instantiated from here
>temp.cpp:11: warning: converting to `int' from `double'
>
>Why?
>Line 16 should not be reached when the function is called
>from line 11.
>Is there any way to avoid this warning?
>Thank you
>Chris

You missed a little fine point from Peter J.:

template <class T>
T GetValue(T t) {  // <--note the parms
    if (t == 1)    // <-- note the '==' compare, NOT '=' assignment.
        return 1;
    else
        return 2.55;
}

--
Bob R
POVrookie