Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ?

[Sisyphus]

----- Original Message ----- 
From: "Rhys Ulerich" <address@hidden>
To: "Richard Haney" <address@hidden>
Cc: <address@hidden>
Sent: Tuesday, September 25, 2012 2:34 AM
Subject: Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ?


> Hi Richard,
>
> > I did a build of gsl-1.15 using gcc.exe (tdm64-1) 4.6.1 under MSYS, and I 
> > used the following command line for configure:
> > ./configure 
> > CFLAGS="-g -O2 -march=native -fexceptions" --prefix=/c/gsl-1.15_64_-g_O2 
> > &> gsl-1.15_configure.out
> > ...
> > ...the config.log has the following line in the "Platform" section 
> > display:
> > uname -m = i686
>
> I would have expected something different from 'uname -m'.  But I know
> nothing about MSYS.
>
> Do the compilation messages echoed by 'make' omit the -march=native
> flag you supplied?
>
> If not, can you compile a small test binary with -march=nature and -S
> that should contain, say, SSE instructions and observe them in the
> output assembly.
>
> If so, then I'd dig into the reason behind the weird 'uname -m' output.

FWIW my MSYS shell outputs the same for 'uname -m'.
I build both 64-bit and 32-bit versions of gsl-1.15 (both dynamic and 
static) in that shell and I've not experienced any problems .... but then I 
also haven't tried supplying the CFLAGS argument that Richard is using.
In fact, I don't provide any CFLAGS arg at all. (I think this means that 
'-g -O2' (as specified by configure script ?) is used.)

Cheers,
Rob