Re: Don't understand VPATH and -l prerequisites

[Paul D. Smith]

%% Barry D Benowitz <address@hidden> writes:

  bdb> VPATH =/my/library/path

  bdb> target : target.o -lmylib

  bdb> What happened was it found the library (libmylib.a) generated the
  bdb> full path to it (ie /my/library/path/libmylib.a) and included
  bdb> that.

Yes, this is exactly what the manual says will happen.

  bdb> What I hoped would happen is that it would maintain the -l so
  bdb> that the library would be searched, instead of included. How can
  bdb> I do this?

Any number of ways.  For example:

  LIBS = -lmylib

  VPATH = /my/library/path

  target: target.o $(LIBS)
        $(CC) -o $@ $(filter-out %.a,$^) $(VPATH:%=-L%) $(LIBS)

-- 
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