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Re: transforming text
From: |
Maciej Walezak |
Subject: |
Re: transforming text |
Date: |
Fri, 22 Feb 2002 15:32:26 +0100 |
Yeah, it works great!
Interesting trick.
Thanks!
> Hi,
>
> Here is one of the solution which works fine.
>
> _empty_ :=
> _space_ := $(_empty_) $(_empty_)
> DCLDEF = foo=path/foo.dcl bar=path/bar.dcl a_junk=a_path/junk.sc
> TEST = $(filter-out %=,$(subst =,=$(_space_),$(DCLDEF)))
>
> default:
> @echo $(DCLDEF)
> @echo $(TEST)
>
> regards
>
> Bhaskar G
>
> SSD/DTG/CTO
> PS DCC - B,
> Philips Innovation Campus, 1&2 Murphy Road,
> Ulsoor, Bangalore 560 008.
> Mail: address@hidden
> ____________________________________________________
> "I find that the harder I work, the more luck I seem to have. "
>
>
>
>
> Maciej Walezak
>
> <address@hidden To: address@hidden
>
> -tech.net> cc: (bcc: Bhaskar
> G/BTC/SC/PHILIPS)
> Sent by: Subject: transforming
> text
> address@hidden
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> org Classification:
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>
>
>
>
> 02/22/02 11:34 AM
>
> Please respond to
>
> help-make
>
>
>
>
>
>
>
>
>
>
> Hello,
>
> I have the following variable:
>
> DCLDEF = foo=path/foo.dcl bar=path/bar.dcl a_junk=a_path/junk.sc
>
> I want to have another variable containing the same list but without the
> prefix *= i.e.
> path/foo.dcl path/bar.dcl a_path/junk.sc
>
> How can I do that? $(patsubst %=,,$(DCLDEF)) does not work.
>
> greetings
> --
> Maciej Walezak
> -GDN-
>
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--
Maciej Walezak
-GDN-