Re: shell function and $PATH

[Tim Murphy]

Why not say

$(shell PATH:=$(PATH) ;  pkgconfig ..,)

?

Regards, Tim
On 17 Dec 2015 4:46 a.m., "Cristian Morales Vega" <address@hidden>
wrote:

> When using this Makefile
>
> ------------
> export PATH:=la:$(PATH)
>
> $(info $(shell echo $$PATH))
>
> all:
>     @echo $$PATH
> ------------
>
> The output is
> $ make
>
> /usr/lib64/qt-3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin
>
> la:/usr/lib64/qt-3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin
>
> The PATH is not being exported to the shell from $(shell), but it is
> to the shell used to run the rules.
>
> This is being a problem for me because I am trying to use $(shell
> pkg-config --cflags <pkg>) with pkg-config from the OpenWRT
> (https://openwrt.org/) toolchain, which is actually a script calling
> pkg-config.real... in the PATH from OpenWRT.
>
> I am using make 4.0, from Fedora 23. Is this a bug, or expected? If
> it's expected... any suggestion about how to solve my pkg-config
> problem?
>
> Thanks.
>
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