Re: Re[2]: How to order make do the parallel job?

[Paul Smith]

On Tue, 2015-12-22 at 09:17 +0300, Igor Sobinov wrote:
> My OS is RHEL 6.6, make version is 3.81
> 
> I used CMake to generate makefiles, only the first makefile is 
> manually created.  The command to execute is:
> 
> .PHONY : build_release1
> build_release1: $(RELEASE_TARGET)
>         +(@cd $(RELEASE_TARGET); $(MAKE) release -j10)

Please always CC the mailing list rather than replying to individuals
directly.

When reporting that a command fails always include the exact command
line you invoked and the error messages (plus maybe a few lines of
output for context).

Your new error is the syntax above: the "@" is a special character for
make and cannot be inside the parenthesis.  The recipe line must be:

    +@(cd $(RELEASE_TARGET); $(MAKE) release -j10)

However, the parentheses here are redundant: make always runs every
command in a subshell so there's no need for parentheses.  Also, you
should use "&&" between the commands so that if the first one (the "cd")
fails, make won't try to run the sub-make.  And finally, the "+", while
it won't hurt, is not needed because you are using the variable $(MAKE)
in the recipe so make already knows it's a submake:

    @cd $(RELEASE_TARGET) && $(MAKE) release -j10

However, it's not a good idea to add an explicit "-j10" here.  You are
invoking "make build_release" with the "-j10" argument so it should not
be here.  This should just be:

    @cd $(RELEASE_TARGET) && $(MAKE)

and that's all.