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Re: tarlz : can't understand option "--output=<file>"
From: |
Antonio Diaz Diaz |
Subject: |
Re: tarlz : can't understand option "--output=<file>" |
Date: |
Thu, 30 Sep 2021 17:14:13 +0200 |
User-agent: |
Mozilla/5.0 (X11; U; Linux i586; en-US; rv:1.9.1.19) Gecko/20110420 SeaMonkey/2.0.14 |
Hi Fractal,
101@mailu.io wrote:
I was trying to compress a folder using tarlz.
I guess you mean you were trying to archive a folder with '-c'. (Tarlz has
an option named '--compress').
I used the option '--output=path/to/some/file'
But it seemed like I was getting garbage output in my terminal.
This is because option -f was absent and the archive was being written to
standard output (the terminal).
I assumed that is the option for output file .i.e the archive.
Yes, but only when compressing an existing POSIX tar archive with '-z'.
Maybe I should make '-o, --output' a synonym for '-f, --file' when creating
an archive.
Anyway '--file=<archive>' seems to do the work that I was trying to do.
But then, '--output=<file>' is not clear to me. What does it do?
http://www.nongnu.org/lzip/manual/tarlz_manual.html#Invoking-tarlz
-o file
--output=file
Write the compressed output to file. '-o -' writes the compressed
output to standard output. Currently '--output' only works with '--compress'.
Best regards,
Antonio.