Re: How to run bash script?

[admin-at-extremeshok-dot-com]

the monit check is like this
## eXtremeSHOK.com
check program contego with path "/etc/monit/scripts/contego"
   group CONTEGO
   start program = "/etc/init.d/contego start" with timeout 900 seconds
   stop program = "/etc/init.d/contego start"
   if status != 0 then stop #restart
   if 5 restarts within 5 cycles then alert
## eXtremeSHOK.com

============

Should work ;-P

## eXtremeSHOK.com
errorcount=`tail -n 10 /mnt/vouchers/contego.log | grep "Error" | wc -l`
if [ $errorcount -gt 0 ] ; then
  echo "OK working"
  exit 0
else
  echo "$errorcount" 1>&2;
  exit 10
fi
## eXtremeSHOK.com

On 3/20/2014 3:39 PM, Martin Vaner wrote:

Hello all,

i have a one question.
I am using monit to monitor all of our servers all around the world, but i have a little problem in this moment.

I need to monitor one log file using external bash script (logtest.sh):

#!/bin/bash
errorcount=`tail -n 10 /mnt/vouchers/contego.log | grep "Error" | wc -l`
if [ $errorcount -gt 0 ]; then
exit 0;
else
exit $?;
fi

So, when i run this script from the console, it is working fine. I tried to do test in the monitrc file, as described here: http://goo.gl/LviXBV (monit official how to):

check program contego_errors with path /usr/local/bin/logtest.sh
    if status != 0 then alert

I also tried to put quotes in the path, but monit still getting this error:

Failed to execute '/usr/local/bin/logtest.sh' -- Exec format error

Do you have some tips & tricks, how can i run this script to test what i need? I also tried something like:

"/bin/bash '/usr/local/bin/logtest.sh'" and any other combinations of "" and '' ... And i am still getting the same error.

Thank you,

Regards,

Martin

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