[Octave-bug-tracker] [bug #55995] "continue" is dynamically, not lexically scoped - callable from functions without for loops

[John W. Eaton]

Follow-up Comment #4, bug #55995 (project octave):

Fixing continue to work like break is fairly simple.  See the attached patch.

In Matlab, is this a parse error, or a run-time error?  I think you could
check with something like


function foo (cond)
  if (cond)
    break;
  end
end


and if this fails with an error when you execute "foo (false)", then it looks
like a parse error to me.  If it only fails when executing "foo (true)", then
we are still not compatible because Octave detects break outside of a loop
when the function is parsed.

I don't remember whether I asked this question when I made break error when it
appears outside of a loop, but it occurs to me now...


(file #46639)
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