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@(x) plus(x,++j)
From: |
Muhali |
Subject: |
@(x) plus(x,++j) |
Date: |
Fri, 23 May 2014 02:37:22 -0700 (PDT) |
I am not sure what to do with this, and whether it is a bug or not.
Letting
j = 0 ;
f = @(x) plus(x,++j) ;
one gets the (expected?) results
octave> feval(f)
ans = 1
octave> feval(f)
ans = 2
etc. But why do I get this
octave> feval(@(x) plus(x,++j))
ans = 1
octave> feval(@(x) plus(x,++j))
ans = 1
etc. ?
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- @(x) plus(x,++j),
Muhali <=