Re: [PATCH 4/7] softfloat: do not set denominator high bit for floatx80 remainder

[Richard Henderson]

On 6/5/20 12:01 PM, Joseph Myers wrote:
> The floatx80 remainder implementation unnecessarily sets the high bit
> of bSig explicitly.  By that point in the function, arguments that are
> invalid, zero, infinity or NaN have already been handled and
> subnormals have been through normalizeFloatx80Subnormal, so the high
> bit will already be set.  Remove the unnecessary code.

Reviewed-by: Richard Henderson <richard.henderson@linaro.org>


r~