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Re: Tramp no longer connects to aws instances
From: |
Michael Albinus |
Subject: |
Re: Tramp no longer connects to aws instances |
Date: |
Sat, 26 Oct 2019 15:20:03 +0200 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/27.0.50 (gnu/linux) |
Frederick Bartlett <address@hidden> writes:
Hi Fred,
> Here's your shell experiment (same result as from inside Emacs):
>
> $ ssh -l ec2-user -o ControlMaster=auto -o ControlPath='tramp.%C'
> -o ControlPersist=no -e none xx.xxx.xxx.xxx
> address@hidden: Permission denied
> (publickey,gssapi-keyex,gssapi-with-mic).
>
> And here's my usual ssh command (which works):
>
> ssh -i <path_to_public_key_file> -o ServerAliveInterval=5 -o
> ServerAliveCountMax=1 address@hidden
The difference is "-i <path_to_public_key_file>". Is it located
somewhere else but in ~/.ssh? An unusal name? And is it really a public
key file? Ususally, "-i" specifies the identity (private key) file.
> Could I edit the Tramp command in Emacs to include a reference to
> public key?
Sure. Have a look at tramp-methods. There is an entry like
--8<---------------cut here---------------start------------->8---
("ssh"
(tramp-login-program "ssh")
(tramp-login-args
(("-l" "%u")
("-p" "%p")
("%c")
("-e" "none")
("%h")))
(tramp-async-args
(("-q")))
(tramp-remote-shell #1#)
(tramp-remote-shell-login
("-l"))
(tramp-remote-shell-args
("-c")))
--8<---------------cut here---------------end--------------->8---
You could overwrite the tramp-login-args element, via a connection
property "login-args". Consult the docstring of tramp-methods for the
meaning of the %x templates. And consult the Tramp manual about
connection properties at (info "(tramp) Predefined connection
information")
Alternatively, you could add an entry in your ~/.ssh/config like this:
--8<---------------cut here---------------start------------->8---
Host foo
HostName xx.xxx.xxx.xxx
User ec2-user
IdentityFile /path/to/identity/file
--8<---------------cut here---------------end--------------->8---
With this, you can use Tramp via "/ssh:foo:". And also in your shell,
you can call directly "ssh foo".
> Thanks,
> Fred
Best regards, Michael.