[Bug-apl] Substring replacement in APL

[Elias Mårtenson]

I had a need to to replace substrings with a replacement, and I'm having a hard time coming up with an concise solution. What I need to do is this:

      'foobartestfootest' replace 'foo' 'xy'

Should yield:

      'xybartestxytest'

Any suggestions?

Regards,

Elias