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Re: [Discuss-gnuradio] BER AWGN example - question


From: Martin Braun (CEL)
Subject: Re: [Discuss-gnuradio] BER AWGN example - question
Date: Mon, 9 Dec 2013 12:13:45 +0100
User-agent: Mutt/1.5.21 (2010-09-15)

On Mon, Dec 09, 2013 at 03:10:49AM -0800, bieniu wrote:
> Martin Braun (CEL) wrote
> > Given an E_b of 1, what is the noise *voltage* (i.e. the expected
> > amplitude of the AWGN process) that will cause an E_b / N_0 of x, if E_b
> > / N_0 is given in dB?
> > If you take pencil and paper, and solve for the noise voltage, you'll
> > get this equation.
> 
> Thank you very much for your reply. I am capable of simple converting value
> in [dB] to the one in [W/W] but I don't know why there are the
> number_of_bits_per_symbol parameter and the '2' constant in the equation.
> It's probably trivial but I would really appreciate your help on this.

The number_of_bits_per_symbol is for E_s -> E_b conversion and the 2 is
for two-sided noise power to one-sided conversion (or was is the other
way 'round? I always mix those up :).

MB

-- 
Karlsruhe Institute of Technology (KIT)
Communications Engineering Lab (CEL)

Dipl.-Ing. Martin Braun
Research Associate

Kaiserstraße 12
Building 05.01
76131 Karlsruhe

Phone: +49 721 608-43790
Fax: +49 721 608-46071
www.cel.kit.edu

KIT -- University of the State of Baden-Württemberg and
National Laboratory of the Helmholtz Association

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