Re: String allocation

[Eli Zaretskii]

> From: qiang <address@hidden>
> Date: Sat, 12 Nov 2011 23:01:50 -0700
> 
> #define NEXT_FREE_LISP_STRING(S) (*(struct Lisp_String **) (S))
> 
> I understand S is a pointer to a Lisp_String, how can the following code
> construct a free_list ?
> 
> for (i = STRING_BLOCK_SIZE - 1; i >= 0; --i)
>       {
>         s = b->strings + i;
>         NEXT_FREE_LISP_STRING (s) = string_free_list;
>         string_free_list = s;
>       }

After this loop is done, what will be in each element of the array
b->strings?