[Regexp] How to use literal $ amounts in replace string for RE.substituteA ll(String,String)

[Jonathan . Cogley]

All,

I have looked through the past mailing lists but couldn't find any mention of 
this issue so I apologize in advance if it has come up before.  

I am using the following code:

    String str = "The socks are: <price/>";
    try {
        RE re = new RE("<price/>");
        System.out.println(str);
        str = re.substituteAll(str,"2 for $1.25");
        System.out.println(str);
    } catch (REException ree) {
         System.out.println("An REException occurred.");
         System.out.println(ree.getMessage());
         ree.printStackTrace();
    }

Output:
The socks are: <price/>
The socks are: 2 for .25

I understand that the $1 represents a sub expression in my regexp which is "" 
because I don't define a sub expression.  I tried escaping the $1 as \$1 but 
still the same results.  Tracing through the source to 
REMatch.substituteInto(String) I noticed that the code does not check for any 
form of escaping around $digit values in the replace string.  

1) How do I escape the dollar value as a literal string?

2) Out of curiosity, why does gnu.regexp use $1,$2,$3,etc when Perl uses 
\1,\2,\3 for sub expressions?

TIA,
Jonathan