RE: [Regexp] How to use literal $ amounts in replace string for RE.substituteA ll(String,String)

[Jon Hoffman]

Hi,

There's a provision for this in the API. 

For instance you can do this:

str = re.substituteAll(str,"2 for $1.25", 0, RE.REG_NO_INTERPOLATE);

See the javadoc for more info.

Hth,

Jon

> -----Original Message-----
> From: address@hidden
> [mailto:address@hidden Behalf Of
> address@hidden
> Sent: Thursday, May 16, 2002 6:37 AM
> To: address@hidden
> Subject: [Regexp] How to use literal $ amounts in replace string for
> RE.substituteA ll(String,String)
> 
> 
> All,
> 
> I have looked through the past mailing lists but couldn't find 
> any mention of this issue so I apologize in advance if it has 
> come up before.  
> 
> I am using the following code:
> 
>     String str = "The socks are: <price/>";
>     try {
>         RE re = new RE("<price/>");
>         System.out.println(str);
>         str = re.substituteAll(str,"2 for $1.25");
>         System.out.println(str);
>     } catch (REException ree) {
>          System.out.println("An REException occurred.");
>          System.out.println(ree.getMessage());
>          ree.printStackTrace();
>     }
> 
> Output:
> The socks are: <price/>
> The socks are: 2 for .25
> 
> I understand that the $1 represents a sub expression in my regexp 
> which is "" because I don't define a sub expression.  I tried 
> escaping the $1 as \$1 but still the same results.  Tracing 
> through the source to REMatch.substituteInto(String) I noticed 
> that the code does not check for any form of escaping around 
> $digit values in the replace string.  
> 
> 1) How do I escape the dollar value as a literal string?
> 
> 2) Out of curiosity, why does gnu.regexp use $1,$2,$3,etc when 
> Perl uses \1,\2,\3 for sub expressions?
> 
> TIA,
> Jonathan
> 
> 
> 
> 
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