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Re: Newbie Conditional Problem


From: Friedrich Dominicus
Subject: Re: Newbie Conditional Problem
Date: 18 Jan 2003 18:03:45 +0100
User-agent: Gnus/5.0808 (Gnus v5.8.8) XEmacs/21.4 (Native Windows TTY Support)

chris@grierwhite.com (Christopher J. White) writes:

> >>>>> "fd" == Friedrich Dominicus <frido@q-software-solutions.com> writes:
> 
> fd> let us try to understand your code
> 
> fd> (let ((line (current-line)))  ;; this give you a simple number with my
> fd> current-line (if that is what you want)
> fd>         (forward-word 1) moves forward onw word from point
> fd>         (if (> (current-line) line) ;; if we moved one line down
> fd>            ;; assuming you meant
> fd>         (progn (goto-line line) (end-of-line))))
> fd>         ;; this means go back one line (back to the line you started from
> 
> fd> But what does it give you? It makes no sense. The code just moves you
> fd> to the end of the current line that is simply to call (end-of-line)
> fd> not more
> 
> As I understand it, it's a forward-word function that keeps the
> cursor on the current line.
Well I suggest you try it go to the end of a line and run 
M-x forward-word you'll be on the next line after the first word.
In this case
is current-line > line -> I go back one line with (goto-line) and
there I move to the end of the line if I' do not move down line
nothing will happens. So what is it if you move move forward a word
and move down a line you go back and than to the end of the current
line. That makes no sénse.


>  If forward-word would move the cursor
> beyond the current line, just go to the end of the (current) line.  
> Could be useful I suppose.
For what?

Friedrich


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