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Re: Problem with position and find (cl)
From: |
Florian Beck |
Subject: |
Re: Problem with position and find (cl) |
Date: |
Fri, 20 Jun 2008 22:14:05 +0200 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/23.0.60 (gnu/linux) |
Marc Tfardy <m-t-o___CUT__IT@web.de> writes:
> Marc Tfardy schrieb:
>> I try with:
>> (member '(2) '((1) (2) (3) (4)))
`member' tests the components: ›2‹ ist always equal (in the sense of »eq«) to
›2‹
Compare:
(memq '(2) '((1) (2) (3) (4)))
(eq 2 2)
(eq '(2) '(2))
>>
>> and this gives a expectet results ((2) (3) (4)), but:
>> (find '(2) '((1) (2) (3) (4)))
>> or
>> (position '(2) '((1) (2) (3) (4)))
>>
>> returns nil. Why?
Because the first and the second »(2)« have the same components but are
*different* lists.
> But this works:
>
> (position '(2) '((1) (2) (3) (4)) :test (lambda (x y) (eq (car x) (car
> y))))
>
> Maybe position and find (and maybe some others functions)
> can not compare lists directly?
They can, but again, the elements are not identical. Compare:
(let* ((x '((1) (2) (3) (4)))
(y (cadr x))
(z '(2)))
(message "x: %s; y:%s" (position y x) (position z x)))
y ist the same object as the cadr of x, z is an entirely new object that
happens to have the same component.
>
> Marc
--
Florian Beck
Re: Problem with position and find (cl), Thien-Thi Nguyen, 2008/06/20