Re: How to translate `rx' expressions to `rx-to-string'?

[Nicolas Richard]

Thorsten Jolitz <tjolitz@gmail.com> writes:
> Seems I did not get the syntax for function rx-to-string yet - any hints
> would be welcome.

Read the code of rx.

(format "%S" (rx bol "foo_" (+ word) eol))
=> "\"^foo_[[:word:]]+$\""

(format "%S" (rx-to-string '(and bol "foo_" (+ word) eol) t))
=> "\"^foo_[[:word:]]+$\""

HTH,

-- 
Nico.