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Template parameter as a friend
From: |
Dmitry Chumack |
Subject: |
Template parameter as a friend |
Date: |
Fri, 01 Jun 2007 09:49:36 -0700 |
User-agent: |
G2/1.0 |
hi *
I have a question, why I can't declare template parameter as a friend?
Here is some example:
//--------------------------------------------------
template <typename T>
class Some
{
friend class T;
public:
Some() {}
private:
T* a;
};
template <typename T>
class Other
{
public:
Other() {}
private:
T a;
};
int main()
{
Some<Other<int> > s;
return 0;
}
//--------------------------------------------------
When I try to compile it using g++ 3.4.6 I got such an error: "using
typedef-name T after class"
When I change class to typename I get such error: "expected nested-
name-specifier before T", "ISO C++ forbids declaration of `T' with no
type", "`T' is neither function nor member function; cannot be
declared friend"
thanks in advance
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