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shorten beamed stems without overriding beam-positions?
From: |
Roland Goretzki |
Subject: |
shorten beamed stems without overriding beam-positions? |
Date: |
Thu, 23 Sep 2004 02:01:03 +0200 |
User-agent: |
Mutt/1.5.5.1+cvs20040105i |
Hi at all.
I'm using version 2.2.0
and want to shorten many beamed stems in a way, which allows to
transpose the whole score afterwards several times, so I cannot use e.g.
\override Beam #'positions = #'(2 . 0).
In my short example at the bottom I can't find a way to shorten the
stems enough. :-(
With \override Stem #'beamed-lengths = #'(1) there is no way.
I also made experiments with minimum-free-lengths and
extreme-minimum-free-lengths, but no result.
It seems, as if one could only make the stems longer ...
e.g. with \override Stem #'beamed-lengths = #'(7)
Can somebody help me, please?
Best Regards Roland
Example:
=======================================================================
\include "deutsch.ly"
\score {
\context Staff \notes \transpose c' c' {
\relative c'' {
\key c \major
<< { \shiftOnn
\override Stem #'beamed-lengths = #'(1)
\times 2/3 { g8 h d }
\times 2/3 { g, h d }
}
\\
{ c,2 }
\\
{ e'2 }
>>
}
}
}
=======================================================================
- shorten beamed stems without overriding beam-positions?,
Roland Goretzki <=