Re: doesn't count triplets beginning on offbeat

[Paul Scott]

Jay Hamilton, Sound and Silence wrote:

> I have windows 2.6.1
> I entered
>
> \times 2/3 {f 8 [ges ges]} ges c, f4 f 16 ges d bes
> c 16 ges f 8 es 16 f d es c 8 c' a bes 8~ \fermata
> bes 8  es,( ges bes ) es, ( ges bes ) es,
> ges 8  d' ( es d ) c 4 ~ c 16 d 8. ~
> \time 7/16
> d 16 [ es, 32 es d 16 ] ~ d 8 [ c 32 c bes 16 ]~
> \time 5/4
> b 8 a ~ a 4. \breathe \times 2/3 d 8 [c d ] \times 2/3 es [ ges bes ] a ~
> \time 5/8
> a 8 \times 2/3 ges [ f es ] \times 2/3 c [d c ]
> \time 4/4
> \times 2/3 es [ ges f ] c' 4 bes 8. bes 16 bes 4

You need curly braces around anything following an operator like \times 
2/3 so Lily will know what to apply the operator to (just as you did 
correctly for the first triplet above).  I also suggest you give a time 
value to anything enclosed in \times x/y { a8 ... }.  I would have to 
guess what type of triplets you wanted

> b 8 a ~ a 4. \breathe \times 2/3 { d 8 [c d ] } \times 2/3 { es [ ges 
> bes ] } a ~
> \time 5/8
> a 8 \times 2/3 { ges [ f es ] } \times 2/3 { c [d c ] }
> \time 4/4
> \times 2/3 { es [ ges f ] } c' 4 bes 8. bes 16 bes 4

Paul Scott

> But in the measure  of 5/4 the triplets are beamed correctly but not 
> labeled as triplets and the barline is before not after the a ~
> So the 5/8 time signature is now in the middle of the measure and the 
> 4/4 time signature is too.  In fact the triplet in the 4/4 measure is 
> not labeled either.
> So it is as though a triplet beginning on the offbeat is not something 
> recognized by this version?
> Or did I enter something wrong?
> Jay