Re: visual problem on two triplets in 4/4 time

[Phil Holmes]

Simply compiling and displaying the code you supplied gives 2 crochets and then 2 pairs of beamed triplets.  It's not 6 notes beamed together.  I'd guess that you have over-ridden some beaming setting elsewhere in your score.

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Phil Holmes

 

 

----- Original Message -----

From: 胡海鹏 - Hu Haipeng

To: lilypond-user

Sent: Friday, September 24, 2010 4:25 PM

Subject: visual problem on two triplets in 4/4 time

Hello,
  My mother found a problem when I write continuous triplets. For example,

\time 4/4 c'4 c' \times 2/3 { c'8 d' e' } \times 2/3 { f' g' a' }

The two triplets are grouped like one sextupplet, but with two 3's. What's the problem? Is it a wrong practice in notation convention? Is it controlled by beam settings?

Regards
Haipeng

 

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