Re: Drawing a hexagon with a number inside

[Rachael Thomas Carlson]

Hello David:

Thanks for the help.

> Those are not actually proper hexagons, so they are pretty easy to draw
> using something like
>
> \markup \path #0.25 #'((moveto 3 0)
>                         (lineto 1 2)
>                         (lineto -1 2)
>                         (lineto -3 0)
>                         (lineto -1 -2)
>                         (lineto 1 -2)
>                         (closepath))
>
> There needs to be scaling and matching to the content as well, of course.

here is what I came up with from your recommendation:

\markup { \override #'(font-name . "Arial")
  {
    \center-column {
    \combine
\path #0.1 #'((moveto 0.9 0)
                       (lineto 0.4 0.7)
                       (lineto -0.4 0.7)
                       (lineto -0.9 0)
                       (lineto -0.4 -0.7)
                       (lineto 0.4 -0.7)
                       (closepath))
\override #'(font-size . -4)
\halign #CENTER
\raise #-0.5
"7"
}
  }
}

I hate to use Arial but the publishing house that I am emulating uses 
only proprietary fonts.

Thank you for the help!

Rachael