[Qexo-general] Problem with symbol scope in concatenation operator (, )

[Stefano Santoro]

Hi,

again a newbie question:

Is it ok if the right operand in a concatenation operation does not
see symbols?

(: 154 :) let $i := 2, $j := $i - 1 return $i, $j
gnu.mapping.UnboundSymbol: Unbound symbol j
        at 
gnu.expr.Interpreter.getDefaultSymbolValue(Interpreter.java:651)
        at gnu.expr.Interpreter.getSymbolValue(Interpreter.java:658)
        at atInteractiveLevel.apply(<stdin>:154)
        at gnu.mapping.CallContext.runUntilDone(CallContext.java:289)
        at gnu.expr.ModuleExp.evalModule(ModuleExp.java:188)
        at kawa.Shell.run(Shell.java:233)
        at kawa.Shell.run(Shell.java:180)
        at kawa.Shell.run(Shell.java:167)
        at kawa.Shell.run(Shell.java:154)
        at kawa.repl.main(repl.java:650)
 2
 
I ask because with a + operator it works

(: 155 :) let $i := 2, $j := $i - 1 return $i+ $j
 3

Ciao
Stefano