[Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined

[hjl.tools at gmail dot com]

https://sourceware.org/bugzilla/show_bug.cgi?id=27210

H.J. Lu <hjl.tools at gmail dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
         Resolution|---                         |NOTABUG
             Status|UNCONFIRMED                 |RESOLVED

--- Comment #1 from H.J. Lu <hjl.tools at gmail dot com> ---
(In reply to Fangrui Song from comment #0)
> cat > a.s <<eof
> .globl foo
> .symver foo, foo@v1
> foo: nop
> eof
> echo 'v1 {};' > a.ver
> cat > b.s <<eof
> .globl  foo_v1
> foo_v1: nop
> .symver foo_v1, foo@v1
> eof
> 
> exit
> 
> 
> GNU ld has a special rule removing foo if foo@v1 is defined. gold and LLD

This is done on purpose. A single '@' defines a 'hidden' versioned symbol,
which is intended for dynamic linker and shouldn't be used by ld to satisfy
the unversioned reference.  ld behavior is correct.

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