Re: Problem with OOT Interpolator Python module

[Cinaed Simson]

Hi George - I'm presuming the enclosed example.py script is what you're trying calculate - and that the input data is complex. 

I invented my own data.

If true, it should be easy to adapt it to your problem by combining the 2 loops for any value of n.

-- Cinaed

On 1/22/21 10:49 AM, George Edwards wrote:

Hello,

I am working with the OOT Interpolator template and I set the interpolation factor to 2. In the QA file I input 5-complex samples  and based on my simple code below in the work() method, I expect the QA test to return 1+j1, 10-times (5x2). The QA returns ((1+1j), (1+1j), 0j,  0j,  0j,  0j,  0j,  0j,  (1+1j) ,  (1+1j)). I have tried a lot of different coding permutations and this is the closest I come to a solution, but it is wrong!!!  Any help is greatly appreciated!

    def work(self, input_items, output_items):

        in0 = input_items[0]

        out = output_items[0]

        for ii in range(0,len(in0)):

            for k in range(0,2):

                out[k] = 1.0+1.0*1j

       

        return len(output_items[0])

 

Thanks,

George 

example.py
Description: Text Data