Re: Debug output

[Paul Pluzhnikov]

Christian Christmann <plfriko@yahoo.de> writes:

> On Fri, 19 Jan 2007 09:18:56 -0800, Paul Pluzhnikov wrote:
>
>> You really ought to read this:
>>  http://www.catb.org/~esr/faqs/smart-questions.html 
>
> I don't think so. "Smart" people can answer your question from
> my first posting. Sorry, if you didn't understand them.

I did understand your question perfectly well.

That doesn't make your question smart, and insisting that it is
doesn't make you look too good either :-(

I've now looked up the original post by Giorgos Keramidas:
http://groups.google.com/group/comp.unix.programmer/msg/6bd69c3b64f0584c
from which you were quoting.

The answer is: there is no way that source produced claimed output --
the source was (obviously) trimmed. Here is the line that was
trimmed from it:

   cout << "l=" << (void*)l << ", pch=" << (void*)pch << endl; 

Cheers,
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