Re: How to switch behaviour according to glibc version?

[David Boyce]

Makefiles are divided between make syntax and shell (recipe) syntax. Here
you're trying to use a shell command (echo) in a place that's not a recipe.
Replace it with $(warning ...) which is the make-syntax equivalent.

On Tue, Apr 5, 2016 at 9:24 AM, David Aldrich <address@hidden>
wrote:

> Hi David
>
> Thanks for your answer to my question. I have one outstanding problem.
> Part of the makefile is now:
>
> ifeq ($(DISTRO),debian)
>   verstr := $(ldd --version | head -1 | awk '{print $NF}')
>   @echo glibc $(verstr) detected
>   ifneq ($(call version_ge,$(verstr),2.22),TRUE)
>     @echo "Warning: system glibc is incompatible with Zodiac so using
> glibc from OPEN_SOURCE_LIBS"
>     GLIBC=$(OPEN_SOURCE_LIBS)/glibc/v2_22/
>     GLIBC_FLAGS=
> -Wl,-rpath=${GLIBC}:${GLIBC}/math:${GLIBC}/elf:${GLIBC}/dlfcn:${GLIBC}/nss:${GLIBC}/nis:${GLIBC}/rt:${GLIBC}/resolv:${GLIBC}/crypt:${GLIBC}/n$
>   endif
> endif
>
> For the first echo statement I get:
>
> Makefile:236: *** missing separator. Stop.
>
> Please can you suggest how I should correct that line?
>
> Best regards
>
> David
>