Re: [igraph] a problem with simplify()

[Tamas Nepusz]

> I am on 0.6 right now. thanks I'll use the workaround, I just need to kill 
> loops. Is there any better way to do this than:
Definitely, because your code does not take into account that edges are 
reindexed after every deletion. I'd go for delete.edges(g, seq(0, 
ecount(g)-1)[is.loop(g)])

-- 
T.