Re: DogCows or Polymorphism in the Hurd

[Patrick Negre]

                Hi, 

Jonathan S. says :

> They will see whatever type was bound for the name they open. In your
> example above, if they open foo.tar.bz, they will see a file. If a
> translator has bound "foo" to a directory view on the same object,
> attempts to open "foo" will see a directory.

Is it really a good idea to create new name in the filesystem tree ? I mean, a 
file must have only one path, create new nodes with binding is confusing.
I don't understand the need of binding the "foo.tar.bz" in a directory "foo".
Isn't it just possible to the application who need the tree view of foo.tar.bz 
to access it as a directory ?

Regards, Patrick N.

        

        
                
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