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Re: [igraph] two-mode network in igraph


From: Simone Gabbriellini
Subject: Re: [igraph] two-mode network in igraph
Date: Fri, 24 Sep 2010 12:41:08 +0200

at this point, I have (first type starts with 100, second type with 200):

> vertices
  [1] "1002"  "1003"  "1006"  "1007"  "1008"  "1009"  "10010" "10011" "10012" 
"10013" "10014" "10015"
 [13] "10016" "10017" "10018" "10019" "10020" "10021" "10022" "10024" "10026" 
"10027" "10028" "10029"
 [25] "10030" "10031" "10033" "10035" "10036" "10037" "10038" "10040" "10041" 
"10042" "10043" "10044"
 [37] "10045" "10046" "10047" "10049" "10050" "10052" "10054" "10055" "10056" 
"10057" "10058" "10060"
 [49] "10061" "10062" "10063" "10064" "10065" "10067" "10068" "10069" "10071" 
"10072" "10073" "10074"
 [61] "10075" "10076" "10077" "10078" "10080" "10081" "10082" "10083" "10084" 
"10085" "10086" "10087"
 [73] "2001"  "2002"  "2003"  "2004"  "2005"  "2006"  "2009"  "20010" "20012" 
"20013" "20014" "20015"
 [85] "20016" "20017" "20019" "20022" "20023" "20024" "20025" "20027" "20026" 
"20028" "20029" "2007" 
 [97] "20030" "20037" "2008"  "2000"  "20021" "20044" "20050" "20043" "20048" 
"20035" "20049" "20056"
[109] "20058"

> edges
  [1]  1002  2001 10087  2009 10086 20010 10085 20016 10085 20013 10085  2005 
10085  2004 10084 20049
 [17] 10083 20019 10083 20016 10083 20010 10083  2009 10083  2004 10083  2002 
10082 20026 10082 20019
 [33] 10082  2002 10081 20029 10081 20010 10081  2009 10080 20019 10080 20016 
10080 20014 10080 20010
 [49] 10080  2002 10078 20043 10078 20016 10078 20010 10078  2009 10077 20022 
10077 20017 10077 20010
 [65] 10076 20012 ...

when I run this I have an error:

bipartite<-graph.bipartite(vertices, edges, directed=TRUE)
Errore in graph.bipartite(vertices, edges, directed = TRUE) : 
  At bipartite.c:438 : Invalid (negative) vertex id, Invalid vertex id

do you have any hint?

regards,
simone

Il giorno 23/set/2010, alle ore 12.21, Tamas Nepusz ha scritto:

>> thanks, that's it! As Tamas has said, I will then convert the network in a 
>> one-mode one
> Actually what I proposed is exactly what you can do with graph.incidence.
> 
> -- 
> Tamas
> 
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