Re: printing bar numbers on every odd measure

[-Eluze]

indeed - much nicer!

so you can put nearly everything in the layout block and keep the music part
"clean" except for the  \bar "" in the beginning - and to suppress the first
bar number, just omit the \bar "" !

the code then could be:

\layout {
  \context {
    \Score
    barNumberVisibility = #all-bar-numbers-visible
    barNumberVisibility = #(lambda (n) (= (modulo n 2) 1))
    \override BarNumber #'break-visibility = #all-visible
} }

\new Staff {
  \bar ""
  \repeat unfold 40 { c'4 c' c' c' }
}

now - will you modify the snippet or shall i try to do that?

cheers
Eluze



Alexander Kobel wrote:
> 
> On 2010-09-22 12:06, Alexander Kobel wrote:
>> On 2010-09-22 11:47, -Eluze wrote:
>>>> On Tue, Sep 21, 2010 at 01:31:00PM -0700, -Eluze wrote:
>>>>> there is also this (quite hidden& undocumented, but working!):
>>>>>
>>>>> \override Score.BarNumber #'break-visibility = #end-of-line-invisible
>>>>> \set Score.barNumberVisibility = #(modulo-bar-number-visible 2 1 )
>>>
>>> added!
>>>
>>> however i didn't manage to build an example where also the very first
>>> barnumber is printed - this seems only to work when the
>>> currentBarNumber is
>>> explicitly set to>1
> 
> Muah, still easier is the following (without the need to change 
> Score.barNumberVisibility again after the first bar):
> 
> %% from your mails and http://lsr.dsi.unimi.it/LSR/Item?id=504
> \score {
>    \new Staff {
>      %% The following are equivalent, but the second variant is more 
> general:
>      %% Change 2 to d in "(modulo n 2)" to show every d-th barnumber.
>      %% E.g. with d=4, {1, 5, 9, 13, ...} will be shown.
> 
>      %% \set Score.barNumberVisibility = #(lambda (n) (odd? n))
>      \set Score.barNumberVisibility = #(lambda (n) (= (modulo n 2) 1))
>      \bar "" %% This is necessary for the first bar number to be printed.
>      \repeat unfold 40 { c'4 c' c' c' }
>    }
> 
>    \layout {
>      \context {
>        \Score
>        \override BarNumber #'break-visibility = #end-of-line-invisible
>      }
>    }
> }
> 
> 
> Cheers,
> Alexander
> 
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> 
> 

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