RE: pp-eval-expression broken

[Drew Adams]

> Does that mean that you will reverse the change to `pp-last-sexp'
> that evals its arg before calling `pp-eval-expression', and let
> `pp-eval-expression' always eval its arg? I hope so.

I see that you made the latter change. Thanks.

However, I think you also need to make the change to `pp-eval-last-sexp'.
Since `pp-eval-expression' evals its arg, `pp-eval-last-sexp' should not
pre-evaluate it; otherwise, it will be doubly eval'd.