Re: divisi parts and another general question

[David Kastrup]

Kieren MacMillan <address@hidden> writes:

> Because I've found that your function (which I used to use) and mine
> (which someone else wrote for me) do two different things — and I want
> the one that yours doesn’t do.
>
> Thanks anyway,
> Kieren.

Kieren, I translated your function right now pretty much literally from
the Scheme expression back to using an embedded LilyPond expression, so
it is quite unlikely that it does something different.

Have you even tried it?

-- 
David Kastrup